Learn in your language
Skip to content
StudyForALearn · Practise · Understand
IGCSE · Cambridge (CIE) · 0580

Position vectors and division of a segment

Find directed segments from position vectors and locate points dividing a line in a stated ratio.

Transformations and vectors pathway · E7.4

Extended only.

Before you begin

  • Add and subtract vectors.
  • Interpret part-to-part ratios.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

How do you express AB from positions a and b?

What you will learn

  • Use AB = b − a from a common origin.
  • Express an internal division point using two position vectors.

Subtract start position from end position

With OA = a and OB = b, the route A to O to B gives AB = −a + b. For a = (1,2), b = (7,5), AB = (6,3). Position vectors are measured from the same origin, while a segment vector begins at its named starting point.

The midpoint M has OM = a + ½(b − a) = ½(a + b). In the example it is (4,3.5). This is an average of positions; the vector AM is half the directed displacement AB, not half the absolute position of B.

Translate a ratio into a fraction of the whole

If AP:PB = 2:1, AP is 2/3 of AB. Therefore OP = a + 2/3(b − a) = 1/3 a + 2/3 b. For A(1,2), B(7,5), the point is (5,4). The ratio is not a factor of two for the entire AB segment.

Read the endpoint order carefully: reversing the ratio to 1:2 locates a different point. For an internal division, the coefficients of a and b sum to one and are both positive. On a diagram, check that the point lies between the endpoints and closer to the endpoint associated with the shorter segment.

Pause and explain

AP:PB = 2:1. What fraction of AB is AP?

Put the idea to work

Worked example

OA = a, OB = b and AP:PB = 2:1. Express OP.

Show the worked solution
  1. AP is two thirds of AB.
  2. AB = b − a, so OP = a + 2/3(b − a).
  3. Simplify to OP = 1/3 a + 2/3 b.

Answer OP = 1/3 a + 2/3 b.

From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

A(−1,3), B(5,−1). Find AB.

Give me a hint

Subtract A's coordinates from B's.

Compare my reasoning
  1. Horizontal displacement is 5 − (−1) = 6.
  2. Vertical displacement is −1 − 3 = −4.
  3. AB = (6,−4).

(6,−4).

Look for these in your work

  • Used end minus start.
  • Preserved direction.
2 · Independent

A(1,2), B(7,5). Find P with AP:PB = 2:1.

Give me a hint

Start at A and move two thirds of AB.

Compare my reasoning
  1. AB = (6,3).
  2. Two thirds is (4,2).
  3. P = (1,2) + (4,2) = (5,4).

P(5,4).

Look for these in your work

  • Converted the ratio correctly.
  • Added the partial displacement to A.
3 · Transfer

OA = a, OB = b. M is the midpoint and N divides AB in ratio AN:NB = 1:3. Express MN.

Give me a hint

Find positions first, then subtract OM from ON.

Compare my reasoning
  1. OM = (a+b)/2; ON = a + (b−a)/4 = 3a/4+b/4.
  2. MN = ON − OM = a/4 − b/4.
  3. Thus MN = −(b−a)/4, pointing back toward A.

MN = (a − b)/4.

Look for these in your work

  • Found both positions from one origin.
  • Checked the backward direction.

Common mistakes

  • Reversing end minus start.
  • Using a part ratio as a whole fraction.
  • Forgetting to add the starting position.
Recall without your notes

What can you explain now?

Why must position vectors share an origin?

Compare with the explanation

Their subtraction then represents the actual displacement.

Mixing origins adds an unaccounted shift and cannot directly produce AB.

After trying it yourself, choose your next review. This is your self-assessment.

Your review choice appears on Today. Sign in to sync it across devices.

Make it stick

Tomorrow, derive an internal ratio-point position and check it using simple coordinates.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Original StudyForA teaching content · AI-assisted checks · Human teacher review pending.

Number contains 19 sequenced lessons; Algebra and graphs 21; Coordinate geometry 10; Geometry 15; Mensuration 13; Trigonometry 13; Transformations and vectors 11; Probability 7; Statistics 13. All 72 syllabus section entries now link to teaching and staged practice. Seven mixed checkpoints sample skills and suggest review lessons. Nine earlier overviews remain available. Full cumulative assessment and human teacher review remain pending. Written lesson practice, charts and constructions are self-checked, not automatically graded. Checkpoints do not save an exam grade or certify mastery.

Check the official syllabus 2025–2027 Open related practice and resources