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StudyForALearn · Practise · Understand
IGCSE · Cambridge (CIE) · 0580

Sine, cosine and tangent for missing sides

Label sides relative to the chosen acute angle and choose the ratio containing the known and unknown sides.

Trigonometry pathway · C6.2 / E6.2

Core and Extended.

Before you begin

  • Identify a hypotenuse.
  • Rearrange equations and use a calculator in degrees.

Work on paper. Try each question before revealing help, and explain why your method works.

Quick readiness check

Which ratio uses opposite and hypotenuse?

What you will learn

  • Identify opposite, adjacent and hypotenuse.
  • Use trigonometric ratios to find a right-triangle side.
θAdjacent AOHypotenuse H
Relative to the marked angle θ, the vertical leg is opposite O, the horizontal leg adjacent A and the sloping side hypotenuse H. Sine is O/H, cosine A/H and tangent O/A. Sketch not to scale.

The chosen angle decides opposite and adjacent

The hypotenuse H is fixed by the right angle. Relative to a chosen acute angle θ, O is the side opposite it and A is the neighbouring leg. The neighbouring hypotenuse does not count as the adjacent leg. Changing the chosen acute angle swaps O and A while H stays fixed.

The ratios are sin θ = O/H, cos θ = A/H and tan θ = O/A. Choose the one containing the two relevant sides. If θ = 30° and H = 10 cm, O = 10 sin 30° = 5 cm. If θ = 40° and A = 7 cm, O = 7 tan 40° ≈ 5.87 cm. Calculator mode must be degrees.

sin θ = O/H; cos θ = A/H; tan θ = O/A

Rearrange before pressing the keys

An unknown numerator usually comes from multiplication: A = H cos θ. An unknown denominator requires division: H = O/sin θ or A = O/tan θ. For O = 6 and θ = 30°, H = 6/0.5 = 12 cm. Multiplying would incorrectly give three, shorter than the given leg.

Draw a side-labelled right triangle, write one ratio equation and isolate the unknown. A quick size check helps: a sine or cosine ratio for an acute angle is between zero and one, so each leg is shorter than H. Retain calculator precision during intermediate steps and round only the final answer.

Pause and explain

Angle θ = 30° and hypotenuse = 10 cm. Find the opposite side.

Put the idea to work

Worked example

In a right triangle, θ = 30° and the opposite side is 6 cm. Find the hypotenuse.

Show the worked solution
  1. The relevant ratio is sin θ = O/H.
  2. Rearrange H = O/sin θ = 6/sin 30° = 12.
  3. Twelve exceeds the given leg six, consistent with a hypotenuse.

Answer 12 cm.

From guided practice to a new situation

Write your answer and reasoning first. Use a hint only if you are stuck. The model solution is for self-checking; your written work is not automatically marked.

1 · Guided

Angle θ = 60° and hypotenuse = 14 cm. Find the adjacent side.

Give me a hint

Cosine uses adjacent over hypotenuse.

Compare my reasoning
  1. cos 60° = A/14.
  2. A = 14 × 0.5 = 7 cm.
  3. Seven is shorter than the hypotenuse fourteen.

7 cm.

Look for these in your work

  • Labelled the adjacent leg correctly.
  • Multiplied the known hypotenuse by cosine.
2 · Independent

Angle θ = 45° and adjacent leg = 9 cm. Find the opposite leg.

Give me a hint

Tangent relates the two legs.

Compare my reasoning
  1. tan 45° = O/9.
  2. Since tan 45° = 1, O = 9 cm.
  3. The two equal legs agree with the 45° right-triangle shape.

9 cm.

Look for these in your work

  • Used tangent rather than a hypotenuse ratio.
  • Checked the equal-leg interpretation.
3 · Transfer

A 10 m ramp rises at 30° to horizontal. Find vertical rise and horizontal run.

Give me a hint

The ramp itself is the hypotenuse.

Compare my reasoning
  1. Vertical rise is 10 sin 30° = 5 m.
  2. Horizontal run is 10 cos 30° = 5√3 m ≈ 8.66 m.
  3. Check 5² + (5√3)² = 100 for the 10 m hypotenuse.

Rise 5 m; run 5√3 m ≈ 8.66 m.

Look for these in your work

  • Distinguished ramp length from horizontal run.
  • Used sine and cosine for the appropriate legs.

Common mistakes

  • Counting the hypotenuse as adjacent.
  • Using the wrong reference angle.
  • Multiplying when the unknown is a denominator.
Recall without your notes

What can you explain now?

What calculator angle mode is needed for these syllabus angles?

Compare with the explanation

Degrees.

The supplied and requested angles are measured in degrees; radian mode gives different ratio values.

After trying it yourself, choose your next review. This is your self-assessment.

Your review choice appears on Today. Sign in to sync it across devices.

Make it stick

Tomorrow, label O, A and H for both acute angles of one triangle, then explain which labels change.

If you needed the solution, close it and solve the problem again from a blank page. A correct answer is stronger when you can explain the reason for each step.

Original StudyForA teaching content · AI-assisted checks · Human teacher review pending.

Number contains 19 sequenced lessons; Algebra and graphs 21; Coordinate geometry 10; Geometry 15; Mensuration 13; Trigonometry 13; Transformations and vectors 11; Probability 7; Statistics 13. All 72 syllabus section entries now link to teaching and staged practice. Seven mixed checkpoints sample skills and suggest review lessons. Nine earlier overviews remain available. Full cumulative assessment and human teacher review remain pending. Written lesson practice, charts and constructions are self-checked, not automatically graded. Checkpoints do not save an exam grade or certify mastery.

Check the official syllabus 2025–2027 Open related practice and resources